Is there a simpler poker game example?

For example, according to 2× 12 = 24, we can get 2× (3+4+5) = 24; According to 3× 8 = 12, we can get 3× (12 ÷ 6× 4) = 24, and so on. Of course, our solution is not unique, we can find it in other ways, but the key is to learn to transform.

What I said above is the case that four numbers are different. If the four numbers are the same, under what circumstances can it be counted as "24"? Let's see, if J, K, Q and A are all regarded as 1, then there are nine situations in which four people draw the same number: four cards 1, four cards 3, four cards 4 ... four 8 cards and four 9 cards. If J, K, Q and A are regarded as 1 1, 12, 13, 1, there are 13 cases. Because the four numbers are the same, it is not good to consider multiplication, and the addition and subtraction relationship can be considered. For example, 12+ 12 = 24, 27-3 = 24 and so on.

Four 1 and four 2' s are too small to calculate "24" even if we multiply them all, so let's exclude them first. From four sevens to four 13, because the number is too big to calculate "24". So, there are only four numbers left: 3-6.

Using 12+ 12 = 24, we can get (6+6)+(6+6) = 24; Using 20+4 = 24, we can get 4× 4+4+4 = 24; With 25- 1 = 24, we can get 5× 5-5 ÷ 5 = 24; With 27-3=24, then we can calculate 3× 3× 3-3 = 24; Suppose that the four cards drawn happen to be four cards in "1-9". Can such cards calculate "24"?

You might as well calculate: there are many ways to make up "24" points, so I won't introduce them one by one. The key is to master the skills.