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∴ When the vehicle is fully loaded, the ground pressure is F=G person +G vehicle =(m vehicle +m person) g = (1300+700) kg× 9.8n/kg =1.96x104n;

When the vehicle is fully loaded, the ground pressure p = fs =1.96×104n4× 250×10? 4m 2 = 1.96× 105 pa；

(2)∫P = Wt，

∴ sightseeing bus normal work 15min power consumption is w = pt = 4000w× 900s = 3.6x106j;

(3) Because the electric sightseeing bus motor works normally, all the electric energy is converted into mechanical energy.

The traction power of an electric vehicle is the same as that of a motor, that is, p machinery =P power,

∫P = Wt = Fst = Fv，

∴ The traction force exerted by sightseeing bus is F=P mechanical v = p electric v = 4000w4m/s = 1000n.

F = f，

The resistance of sightseeing bus is f = f = f =1000n. ..

A:

(1) When sightseeing bus is fully loaded, the ground pressure is1.96×105 Pa;

(2) The normal working time in sightseeing bus is 15min, and the power consumption is 3.6x106j; j；

(3) The resistance of sightseeing bus is1000 n. 。