Fortune Telling Collection - Horoscope - Crimaster crime master classic three encrypted answers summary
Crimaster crime master classic three encrypted answers summary
Crimaster crime master classic three encrypted answers
Classic triple encryption
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Chapter one: pigsty code, chapter two: Etbash code, and chapter three: vowel code.
The pigsty password, also known as the Masonic password, is a simple alternative password based on lattice. Even if symbols are used, it will not affect the cryptanalysis, and other alternative methods can be used. As early as 1700, freemasons often use this password to protect some private records of mdash or for communication, so it is also called the Masonic Code.
In 500 BC, Etbash code was copied to write Jeremiah. This code was used to hide names in the texts of the Essenes Sadoji/Nazarene Sect in the 1 th century.
Vowel cipher is an encryption method which uses numbers instead of letters, and it is a cipher which uses vowels in phonetic symbols to encrypt.
Why not write the origin? Because we can't find who invented it.
Answer: 1. Freeandacceptedsons,2。 MKCHEN, 3.4523103033103513, 4. Sherlock Holmes.
Detailed analysis:
first step
Question: Please enter the meaning of the picture pigsty password.
Answer: FREEANDACCEPTEDMASONS
Analysis:
Graphical password and letter comparison table:
Analysis chart:
The second obstacle
Question: Ciphertext: The code of npxsvm Etbash is encrypted. Please enter the plaintext of this password.
Answer: MKCHEN
Analysis: The English alphabet is as follows. Find the ciphertext according to the line below the table, and then correspond to the plaintext above.
third stage
Question: Please encrypt the word Thailand with vowels and write the ciphertext. Vowels are encrypted with two digits. Please enter the encrypted answer
Answer: 4523103033103513.
Analysis:
According to the password table:
T corresponds to 45; H corresponds to 23; A corresponds to 1, which corresponds to 10 because the title requires that vowels be encrypted with two digits; I corresponds to 3, because the title requires that vowels be encrypted with two digits, so it is against 30; L corresponds to 33; A corresponds to 1, which corresponds to 10 because the title requires that vowels be encrypted with two digits; N corresponds to 35; D corresponds to 13.
Therefore, the encrypted ciphertext is 4523103033103513.
Fourth layer
Question: Please use vowel cipher to decode the following ciphertexts: 23, 4, 33, 34, 2, 44. Please enter the decrypted ciphertext.
Answer: Sherlock Holmes
Analysis: According to the password table
23 corresponds to h; 4 corresponds to o; 33 corresponds to l; 34 corresponds to m; 2 corresponds to e; 44 corresponds to s; Therefore, the plain text is Sherlock Holmes.
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