Intellectual poker game.

The side with more cards can't win. This is not as confusing as chess pieces. To put it bluntly, it is a lie. And there is no technical content.

More cards are played first, and the first one takes the initiative. Generally, the first rule also determines the later trend. This is the characteristic of chess, and there are countless tricks behind it. And this game? No matter how we play, the other party has only one trick, that is to play A, then we can only pay him 20.

We have the right of first in, first out, and seem to have the initiative, but it is not, and there is no chance to arrange the order and combination at all.

First, you can't play a pair, and the pair will lose immediately. The other pair of A's is bigger than all our pairs.

Second, three pairs can't be produced, and the remaining small pairs can only wait for death.

It seems that there are many options to play first, but in fact, only one can be played, that is, 3 or 9. In this way, after the other side plays, we still have a chance to play. Once the opponent starts playing cards, we have no chance to play cards again.

After we give 3/9, let it become 9. When the other side gets an A, the ending is settled. The other party will not give us a 10 as we take it for granted. If someone is cheated, we take it for granted that after we give 3 or 9, he will give us a 10, and then we will win.

In fact, the other party gave an A directly, and we only have the following modes of transportation.

First: go up to 2. There is also an A on the other side, the biggest one. There is also a pair of 10, which is greater than our 55 66 77 88.

Next, if we place an order first, the other party will lose directly with another A; If there is a pair, the opponent will directly play 10, and then we will play Q or K, then the opponent will have an A left. We have three pairs of small cards and two single cards, 3 and Q/K. Only one of the two single cards can be issued, which is also a loss.

Second: No, the other side also has a pair of 10 A. The right to play is on the other side.

Next, the other side couldn't play 10, and the other side lost directly.

The opponent can play an ace, at this time we can only play 2, and the remaining 55 66 77 88 cards will be lost. If you play directly, you lose. These four couples can't play separately. If you play 10 directly, then his 10 is larger than the remaining three cards and the remaining single cards that have just been dismantled. Still lose.

The other party quoted a pair of 10, and we can only handle q or k, so there are two orders of 3 and q or 3 and k, which is also less than the other party's A.

This game is a complete lie. We only consider that he will be fooled if he calls 10 first. He has nothing to hide. He counted every penny he earned. If we have an inevitable way to crack it, he will lose his life.