Probability of dice roll: Event A: three dice rolls and at least one 6-point event B: three dice rolls and at least one 3-point event.

Solution: Let "Events A and B occur at the same time" be Event C, then

The content of event C is: Three dice have at least one three-point and one six-point.

In this case, there are several situations:

(1) 36x (is x the number of points of three or six)

(2)336

(3)366

P(C 1)=A(3，3)× 1/6× 1/6×4/6

= 1/9

P(C2)=C( 1，3)× 1/6× 1/6× 1/6 = 1/72

C3 = C2 = 1/72

So p (c) =1/9+1/72+1/72.

=5/36