Roll two dice in succession, observe the upward points, and ask: (1)*** How many different results are there? (2) What is the probability that the sum of the points obtained is 4?

(1) Each dice has 6 kinds of results, so * * * has 6×6=36 different results.

(2) If event A is "the sum of points obtained is 4", there are three basic events that satisfy event A, namely (1, 3), (2,2), (3, 1).

So p (a) = 336 = 1 12.

(3) Note that event B is "the sum of points obtained is a multiple of 4", so the basic event satisfying event B is (1, 3).

(2, 2), (3, 1), (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), (6, 6) * * 9 cases,

So p (b) = 936 = 14.