Urgently ask the following two questions, don't just say the answers. I know the answer needs to be analyzed in detail.

1) Let the heights of three coins be H 1, H2 and H5.

Then: 6h 1=5h2 h2=6/5 h 1.

6h2=5h5 h2=5/6 h5

So 6/5 h 1 = h2 =5/6 h5.

36h 1=30h2=25h5

That is, 36 coins with 1 minute, 30 coins with 2 minutes, and 25 coins with the same height.

36* 1+30*2+25*5=22 1

So 72* 1+60*2+50*5=442.

So 72 1 coin, 60 2 coins and 50 5 coins.

2)) 72=2*2*2*3*3

So the value of X+6+7+9+Y=22+X+Y should be a multiple of 72.

It should also be a multiple of 9

De: 22+X+Y=27

Or 22+X+Y=36.

Because y can't be an odd number, X 1 = 1 = 4167.94167.94/72 = 2.3325.

X2=3，Y2 = 2 367.92 367.92/72 = 5. 1 1

X3=6，Y3=8 667.98 667.98/72=9.2775

X4=8，Y4 = 6 867.96 867.96/72 = 12.055

So X=3.