(2007? As shown in the picture, there is a stack of 54 playing cards on the horizontal table, each with the same quality as M, standing upright with one finger.

(2) Let the finger pressure on the 1 card be n, and let the n(n=2, 3, 4…53) card slide to the right relative to the n+ 1 card, then the n card will be subjected to the maximum friction (sliding friction or static friction) from the n- 1 card.

Its direction is horizontal to the right

At this time, the sliding friction of the nth card subjected to N+ 1 card is fn=μ2(N+nmg).

Its direction is horizontal to the left.

Compare the two formulas, fn > fn- 1.

In view of the above assumption, the resultant force of the nth card in the horizontal direction is to the left, contrary to the assumption, so the assumption is invalid, that is, any 1 card between the second card and the 53rd card cannot slide to the right relative to other cards.

Answer: (1) impossible;

(2) The certificate is shown above.