Does the lottery order affect the result?

Equality, no matter who smokes first, is fair.

Prove it with a general situation. Suppose there are n lots, m of which are "medium". The probability of the first person drawn is obviously m/n. We randomly draw two tags from n tags, and there are n(n- 1) methods, which is our total sample space. In these arrangements, the second person is guaranteed to win the prize, and he has M lottery ways.

In this way, the first person can choose from the remaining n- 1, and then there are m(n- 1) ways to ensure that the second person can draw. Therefore, the "probability of the second person drawing" is m(n- 1)/n(n- 1), which is still equal to m/n.

The order of drawing lots has nothing to do with the result.

In a similar way, it can be proved that from now on, everyone's chance of winning the lottery is m/n. In fact, this problem has a simpler idea. No matter how these people draw lots, the final result is nothing more than the arrangement and combination of n lots.

In this arrangement, no position is more special than other positions, so the possibility of winning the ticket in each position must be equal. The lottery selection is a fair selection method. If the results are not announced, the lottery order will not affect the winning probability.