The front wheel diameter of the roller is 1.2m, and the wheel width is 2m. How many meters can the front wheel of this road roller advance once? What is the compression area?

The front wheel diameter of the roller is 1.2m, and the wheel width is 2m.

Circumference: 3. 14 * 1.2 = 3.768 meters.

The front wheel of this roller can roll 1 cycle, and the forward speed is 3.768 meters.

Compressive area: 3.768*2=7.536 square meters.

Formulas for expanding data related to circles:

1, area of semicircle: s semicircle = (π r 2)/2. (r is the radius).

2. The area of the circular ring: s great circle -S small circle = π (r 2-r 2) (r is the radius of the great circle and r is the radius of the small circle).

3. Circumference: C=2πr or c = π d..(d is the diameter and r is the radius).

4. The circumference of a semicircle: d+(πd)/2 or d+π r (d is the diameter and r is the radius).

5. Sector arc length L= central angle (radian system) ×R= nπR/ 180(θ is central angle) (R is sector radius).

6. Sector area S=nπ R? /360=LR/2(L is the arc length of the sector)

7. Radius of cone bottom surface r=nR/360(r is the radius of bottom surface) (N is the central angle)

In the sum of infinite small sector areas, so in the last formula, the sum of small arcs is the circumference of a circle, so there is S=πr? .