The date of June 65438+1 October12009 is Thursday. What day is June 65438+February 1 2009? 200 1 1 1?

Different month, year, 7:

3 1÷7 remainder 3,30 ÷ 7 remainder 2,29 ÷ 7 remainder 1, 28÷7 remainder 0,365 ÷ 7 remainder 1, 366÷7 remainder 2

In the same number of days, in

The number of days in big month, small month, leap February and flat February is +3, +2,+1 and +0 respectively.

For the same date, after normal year, leap year and day of the week, the changes are+1 and +2 respectively.

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From June 2009 10 to February 2009 1, two months passed: 09.10,09.11.

4+3+2 = 9,9 ÷ 7+2, so today is Tuesday.

From June 65438+1 October 2009 1 to June 65438+1October 20651,three months have passed, that is, 09. 10.

4+3+2+3= 12, 12÷7+5 So today is Friday.

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/s？ bs = % CD % AC % D3 % E0 % BC % C6 % CB % E3 % D0 % C7 % C6 % DA & amp； f = 8 & ampwd = % D0 % C7 % C6 % DA % B5 % C4 % BC % C6 % CB % E3+-+% CE % AC % BB % F9 % B0 % D9 % BF % C6

June 65438+February 2009 1 is Tuesday, and June 65438+1 October 20091is Monday. Details are as follows:

65438+February 2009

(IV+31(2009.65438+1October)+30 (2009.165438+1October)+1(2009./kloc)

=65 to 7.

= two

200 1 1 1.

Let 200 1 year 1 day week x, 2009 1 month 1 day distance 200 1 month/day be calculated as follows:

365 * 8 (200 1-2008) is a total of 8 years, all of which are calculated according to the average year first. Since it started at 200 1 1, 200 1 can also be regarded as the whole year) +2(2004 and 2008 are two leap years. 1-September, all miscarriages are counted first)-2 (two days less in February 2009)+5 (five big months in 2009,1,3, 5, 7, 8)+1(2009.5008+00.5000000)

=3 195

So there is (X+3 195) to seven = four.

Because 3 195 is the remainder of seven = three.

So x has a minimum solution. Four-three equals one.

So 200 1 1 1 is Monday.