Equivalence of inequality proposition

"t∈R, is it a negative proposition about the inequality m > (T2-1)/(t-2) m ≤ (T2-1)/(t-2)? If so, then the solution sets of these two inequalities should be complementary in R. "

No, the proposition of no is that the inequality m > (t 2-1)/(t-2) does not hold.

Is m > (t 2-1)/(t-2) and m > (t 2-1)/(t-2) max equivalent? "

If the former holds, then it is equivalent.

"Because (t 2- 1)/(t-2) ≤ 4-2 radical number 3, the original inequality is equivalent to the immediate solution of m > 4-2 radical number 3."

No, the former is t when t approaches infinity, that is, there is no maximum.