The mystery of Zhuge Liang's calculation

First of all, each row has the same number of 10 and 100, and each of the six rows takes a number of 100, and the number of 10 adds up to 3000.

Then, the sum of thousands and single digits is the same as that of peers. The first behavior 7, the second behavior 8, the third behavior 1 1, the fourth behavior 9, the fifth behavior 10 and the sixth behavior 12. Six numbers add up, and the sum of thousands and units is 57. At the same time, add "3" to "3000" which is the sum of hundreds and tens, so that the sum of thousands and tens in the final result should be 60.

In this way, when the six numbers are taken out, you only need to calculate the thousand digits (or single digits), and the result plus 3 is the thousand digits of the answer, and the hundred digits are 0. Subtract thousands from 600 to get ten digits.

For example, if we take the first column and all six thousands, we can easily see that the addition is equal to 3 1, plus the "3" of 3000, then the thousand of the answer is 34, the hundred is 0, and 60 MINUS 34 equals 26, so the final answer is 34026.

Take the sixth column as an example, "(6+5+6+ 1+5)+3 = 32" and "60-32 = 28", and the answer is 32028.

So the real algorithm is just to calculate a list of numbers.