Fortune Telling Collection - Comprehensive fortune-telling - Heavenly stems and earthly branches method
Heavenly stems and earthly branches method
Ground branch: (1984-4) ÷12 =165, and the remainder is 0,0+1=1,that is, the ground branch is a "child", belonging to the genus Rattus. The second algorithm: Tiangan algorithm: the year number is divided by 10 (the ground branch is divided by 12), and the remainder is -3, which is the Tiangan (or the ground branch) serial number. The remainder -3, there are three cases: 1, when it is a positive number, the result is a serial number; 2. When it is 0, the serial number is the end, and the sky is dry and the decyl is taken (ground painting); 3. If it is negative, add 10 to calculate the heavenly stems (add 12 to calculate the earthly branches), and the result is the serial number of the heavenly stems (or earthly branches). For example, Tiangan in 2009: 2009 10, the remainder is 9,9-3 = 6, that is, Tiangan 6 is "self"; Gezhi: The remainder of 2009÷ 12 is 5,5-3 = 2, which means Gezhi 2 is ugly and belongs to a cow. Another example is Tiangan in 20 12: 20 12÷ 10, and the remainder is 2,2-3 =-1+10 = 9 is "nonyl"; Gezhi: the remainder of 20 12÷ 12 is 8, and 8-3 = 5, that is, Gezhi 5 is Chen and belongs to a dragon.
First of all, you must be able to remember ten days and twelve branches. Ten days of work are: A, B, C, D, E, G, Xin, Ren and Gui. Twelve earthly branches: Zi, Ugly, Yin, Mao, Chen, Si, Wu, Wei, Shen, You, Xu and Hai;
Heavenly stems and earthly branches's method of chronology is that the heavenly stem is in front and the earthly branch is behind. For example, in 2005, this year is the year of-yiyou. Let's count the days first. There is a formula:
4, 5, 6, 7, 8, 9, 0, 1, 2, 3, the corresponding ten days are
Party A, Party B, Party C, Party D, Party E, Party B, Party G, Party A, Party B, Party B, Party C, Party B, Party B, Party B, Party B,
The number is the last digit of the year, for example, this year is 2005, the last digit is 5, and the corresponding heavenly stems are B;
Earthbranch algorithm: divide the number of years by 12, and the remainder after that represents a earthbranch, and the remainders are: 4, 5, 6, 7, 8, 9, 10, 1 0 (divisible) and/kloc-0 respectively. Take 2005 as an example: the year-end is 5, and the corresponding heavenly stems are B. When 2005 is divided by 12, the remainder is 1, and the corresponding earthly branches are unitary, then 2005 is B year.
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