Who can help me explain the principle of EVE transition curve?

Official website explained that the spacecraft, whether it is an ordinary transition or a curve transition, creates a "capsule" that violates the normal physical laws by absorbing the energy around itself. Take this capsule as an example. If you have an acceleration of 1000m/s, the environment will give you an acceleration of1000 m/s, so that even the engine on the spacecraft can accelerate the spacecraft to superluminal speed in a short time. You may ask, why such a large acceleration? That's because it takes a lot of force for an object to change its state of motion, and it also takes a lot of force to accelerate to superluminal speed in a short time. The fuel on the spacecraft is limited, although the energy is infinite (reactor), but the engine with limited injection speed cannot inject limited fuel with limited injection speed, so it depends on transition.

Ordinary transition and curve transition are only different in energy absorption, one should be rotated and the other should not be. In fact, ordinary transition consumes more energy, and jumping consumes more energy than starting a cycle. Qu Yue needs a lot of energy in battle because you need to turn, which is different from ordinary one-time jump acceleration, so you need more energy. Of course, this is a game after all. In theory, if you completely control a spaceship, you can completely let Qu Yue be laid off and use the jump engine to complete the action.

As for the intergalactic jump, that's another matter. Galaxy jumping, whether flagship or portal jumping, relies on plasma (official website didn't elaborate) to compress the gravity of stars, creating a high-gravity channel and artificial wormholes. In order not to crush the spacecraft, the frequencies of the stargates on both sides will be adjusted, so that the gravity waves on both sides will cancel each other out, and the cancellation point is exactly the position of the spacecraft in the channel. The flagship is much more troublesome, because the other end is not the artificial gate, but the star of the opposite galaxy, which requires higher calculation of the cancellation point of the jumping device.