Is there a scientific relationship between the ebb and flow of tides and the moon's profit and loss?

The ebb and flow of tides has nothing to do with the monthly loss; But it is related to the gravity of the moon;

Regardless of the weak role of other planets, the tidal force of the moon and the sun on the ocean is the reason for the fluctuation of seawater. What kind of force is tidal force? In physics, in the non-inertial system, tidal force is the resultant force of lunar gravity and its corresponding inertial force, as well as solar gravity and its corresponding inertial force. It is mentioned that "centrifugal force" is also one of the components of tidal force. There is a reference to centrifugal phenomenon in physics, but there is no concept and definition of "centrifugal force". However, the original meaning of "centrifugal force" is inertial force.

The gravity of the moon alone can't explain why the two regions of the earth's nearest sea surface and the farthest sea surface appear at the same time, thus turning the spherical sea level into a spindle shape, as shown in the figure. So is the gravity of the sun. By the end of 20 12, the latest physics appeared.

The concept and definition of glume gravity. The content of the definition is: "within the scope of statics, the support or the object itself placed on it is regarded as a non-inertial reference, and gravity is the resultant force of all gravity and inertial forces on the object." This definition can successfully explain the causes of tides. It should be noted here that when the planet is regarded as a particle, only the gravity of the ground object and the inertial force corresponding to the centripetal force of the object rotating with the earth participate in the calculation, and the gravity of other planets is offset by the corresponding inertial force.

Tides are formed for the following reasons:

Let's talk about the role of the moon first. Think of the earth and the moon as particles and say that the moon moves in a circle around the earth. In fact, both the moon and the earth move in a circle around their common center of mass, but the circular orbit of the earth is much smaller. (The circular orbits of two planets with similar mass in a binary star are approximately equal) Taking the center of the earth as a non-inertial reference, the attraction of the lunar particles to the earth particles is the centripetal force of the earth particles moving around the common center of mass, and the inertia forces corresponding to this centripetal force are equal in magnitude and opposite in direction. Therefore, the attraction of the moon particles to the earth particles and this inertia force cancel each other out.

Since the earth is regarded as a particle, the trajectory and dynamics of objects on the earth can be regarded as exactly the same as the earth particle. In this way, the gravity of the moon and the corresponding inertia force cancel each other out.

In fact, the earth is very large. On the ground closest to the moon, the orbital radius of an object moving around the common center of mass of the earth and the moon is obviously smaller than that of a particle on the earth, and the attraction of the moon to the object will be greater than the corresponding inertial force. These two forces can no longer be offset, and their resultant force is opposite to the direction in which the object is attracted by the earth, which makes the gravity of the object obviously smaller. If the "object" is the seawater here, then there will be a climax here. Using the same method to study the objects on the ground farthest from the moon, the gravity of the moon is less than the corresponding inertia force, and their resultant force is opposite to the gravity of the earth, which also makes the gravity of the objects obviously smaller. Therefore, the part of the sea farthest from the moon will also have a climax. This makes the sea level, which should be spherical, slightly spindle-shaped.